Question

Sectn anwering these questions, show all your work in your blue book. 23 The first step in the Ostwald process for producing nitric acid is the reaction of 175g of ammonia with 175. g of oxygen gas yields 101. g of nitric oxide (NO), whs eeS04e)4NOR)+ 6M,Ole) he percent yield of this reaction? 24 24.5 mL ofa 0.1050 M Na CO, solution is added to 75.5.0 mL of 0.1250 M NaCl. What is the concentration of sodium lon in the final solution? 25 The concentration of oxalate ion (C,O,) in a sample can be determined by titration with a solution of permanganate ion (MnO,) of known concentration. The net ionic equation for this reaction is 2Mno,+SC,0+16H- 2Mn+8H,O + 10CO , 4 45.00 ml sample of an oxalate solution is found to react completely with 24.83 mL of a 0.1725 M solution of MnO, What is the oxalate ion concentration in the sample?o luo y me 26. What is the binding energy (kj/mol) of an electron in a metal whose threshold frequency for photoelectrons is 2.50 x 10/s? 25 oi noitsuinoe nottaale tse bnuog toma sdsbivonq ys d wollol od1o c mote sold 27. Write the complete electron configuration for the arsenic (As) atom. Give the n and I quantum numbers for the last three electrons. (Use your periodic table as a guide.) ovods edto nolt

Answer 1

This question is solved as follows:

Sol We are given, 4 NOCG) + 6H₂O(g) 4NH3(g) +50, (g) 175 gm 175gm. t 101 gm 175 Jor n (no. of moles) x 1oo 175 16X2 30 molecular cot. = 10.29 = 3.36 = 5.468 1 yield = moles of product formed experimentally moles of product formed theoretically SNote Theoretically, we get 4 moles of No; which we see in the balanced ion experimentally the yield / moles of product is 3.36 moles. 3:36 yield - x 100 = 0.84 x 100 84% Ang Experimental yield is always lesser than that of theoretical yield; because in experiments there are chances of mistakes and we can not get the exact results we chant. y.