= 9.3
= 1.1
n = 70
SE =
/
= 1.1/
= 0.1315
To find P(
<
9.1):
Z = (
-
)/SE
=(9.1 - 9.3)/0.1315 = - 1.5212
Table of Area Under Standard Normal Curve gives area = 0.4357
So
P(
<9.1)
= 0.5 - 0.4357 = 0.0643
So,
Answer is:
0.0643
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