Please help!
|
Student |
# keys |
Student |
# keys |
Student |
# keys |
|
1 |
0 |
9 |
5 |
17 |
3 |
|
2 |
2 |
10 |
1 |
18 |
3 |
|
3 |
4 |
11 |
5 |
19 |
2 |
|
4 |
2 |
12 |
3 |
20 |
7 |
|
5 |
3 |
13 |
2 |
21 |
3 |
|
6 |
2 |
14 |
4 |
22 |
2 |
|
7 |
0 |
15 |
0 |
||
|
8 |
3 |
16 |
1 |
a)

the distribution of the data looks slightly right skewed.
b) 95% CI for mean number of keys

t0.025,21 = 2.08
Descriptive Statistics
| N | Mean | StDev | SE Mean | 95% CI for μ |
| 22 | 2.59 | 1.74 | 0.370 | (1.82, 3.36) |
μ: mean of Number of keys
c) the values between 1.8 and 3.36 are 2 and 3. there are 12 number of values falls in this range.
the percentage of students sampled to this are 12*100/22 = 54.54%
The percentage should not be close to 95 because the 95% CI means that the mean value of the sample will lie in this 95% CI range for the 95% of the times.
Please help! Student # keys Student # keys Student # keys 1 0 9 5 17...
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