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95 What is the molar solubility of barium fluoride? _ Enter your answer with 3 significant digits with no units and the forma

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Answer #1

The complete step wise calculation is given as below:-

95 for BaFq (Barium fluoride) solubility product is given by: - Ksp = 1.70 X166

Solubility of [Ba2+] = 5 = [FO Then reaction is given by: - Bata Bartraq) + 2F osolubility pro duct ksp for the above equation , we have Ksp = [Bq2f] x [FO2 @ putting all the values in the above equation @

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