On a 20 meter diving board hinged at the right end, sticking out over a pool, where would you place a 40kg person so that it had the greatest torque?
Answer: At the farthest point from the hinge.
If the person was placed at the very end, what is the magnitude of force that keeps the diving board in static equilibrium?
Answer: 7840 N
The answers are given, but I would like to know how to get these answers.
Torque= force*perpendicular distance
![L=2om IT= 40 x g. 8 = 342 N [m] mz 40 kg at Tosque is maximum the farthest polut T= TXL T= (392728) T= 7040 Nm](http://img.homeworklib.com/questions/9e589fe0-73cb-11ea-92c8-31b36d4e95f3.png?x-oss-process=image/resize,w_560)
On a 20 meter diving board hinged at the right end, sticking out over a pool,...
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was answered and laid out. I am not understanding how to go about
this or what formulas to use.
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