Question

8. What volume of a 5.00 M NaNO3 solution should you use to make 0.500 L of a 1.50 M NaNO3 solution? 9. What volume (in mL) of a 0.230 M HNO3 solution will completely react with 21.3 mL of a 0.125 M Na2CO3 solution according to this balanced chemical equation? NazCO3(aq) + 2 HNO3(aq) → 2 NaNO3(aq) + CO2(g) + H200)_

Answer 1

Molarity: Molanity means number of moles of solute present per liter of solution, Molarita moles volume in t is = p { m - smolarity} from the above relation express, we can also nVXM & volume (1) = moles moles a volumex Mola Molarity moles of 1. 50 M Nanoz solution = present 0.500 L X in 0.500 L of 1.50 motes = 0.75 moles. 11 Giren molar concen tration of Nano solution - 5.0m. = 5.00 moles/L : 5.00 moles of Namoz present in 1 L. 0.75 moles of manos present = 12 +0.75 moles 5.00 moles i Required volume-1 Volume [0.157L = 0.15L Another method, me know mivi = M₂ V₂ M = 5.00m M 1.50 m 5.0m V₂ a 0.52 10.15L . V 1.50 mx 0.5L Vovolume

9 The given balanced chemical equation, Mag coz (aq) + 2 NO3 (an 2 Nanozcan & Co (g) f Hadle Now, moles of Naqoz present in 21-3m2 of 0.125 m Solution = 0.0213 LX 125 moles 7 2113 m2; 0.02134) = 2.6625x10 3 mol Now ratio, according to . 1 mole of more of Hroz. a to the stair the stoichiometric Na coz beach with 2 : Moles HNO3 = 1.6625x10 . Magcong = 5.325 710? more les HMS Exlo moles con I sroles - Magaz 225x10 smole ANO volume of time required moles of thoz molar con un tration of Hroz 5.325x10-3 mole 0.230 more x 11 0.02315 - 23:152 m2 . Required volume - 23.152 m