A(aq) = 2B(aq) K = 1.03 x 10- at 500 K If a 1.70 M sample...

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science chemistry

Answer 1

Answer #1

Given, reaction, So A log 2B (ag) equilibrium constant for this reaction, [B]? K = [A] here, [B] = concentration of B and [A]

Answer 2

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