Question

3. (10 pts) The progress of a reaction in aqueous solution was monitored by absorbance measurements of a reactant at various times: Time (s) 0 54 171 390 720 1010 1190 Absorbance 1.67 1.51 1.24 0.847 0.478 0.301 0.216 Tim 54 171 390 720 1010 Determine the order of the reaction and the rate constant.

Answer 1

dus set Rate = K[A] where [A] is concentration of Abdoubance. d[A] = K[ATM solution de at t=0, [A] = 1067 Starting point t=54, TAJ = 1051. 1.51-1067 = K (1067) - elli) 54-0 at t= 54, [AJ = 105, starting point, it = 171, [A] = 1024 1024-105) ck (1.513" -equii) 171-54 eq (1) egli su x (1.24-1.51) K(1.51)" 9.284 = ( 1167) Taking aseti log both stel Log (1284) = m log ( na 2.5 = 5 (1051-1067)x (171-54) = k11.67)

Rate = k SAJ/ eq 0 1051 - 1067 = K (1.67) K=-8.22X10-4 Bell M3% 81 Overall eq. Rate = -8. 22X10" (AJ5/2 Thank you: