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At 25 °C the reaction from Part A has a composition as shown in the table below. Substance Pressure (atm) 3.75 C2H2(g) H2(g)

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Answer #1

Write the chemical reaction: C2H2(g) + 2H2(g) + C2H6(9)

= 0.000952 [CH] 4.25 x10-2 - [C,H,][H, [3.75][3.45] Now AG =-RT InK, =-8.314 x 298 x ln(0.000952) =17235.8J = 17.235kJ/mol

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