Question

solution:

The outcome of rolling a pair of fair dice are

Total outcomes = 36

A)

Now, A wins if the sum of numbers showing up is 6 or less and one of the die shows 4, so this makes (1,4), (4,1), (2,4), (4,2). Hence

probability that A wins = 4/36 = 1/9

B)

B wins if the sum of numbers showing up is 5 or more and one of the die shows 4, so this makes all the bold outcomes in the table.

Probability of B winning = 11/36

C)

Both A and B win when the out comes are (1,4), (4,1), (2,4),(4,2) i.e When A wins. Hence

The probability that both A and B wins = 1/9

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