Question

How many liters of O2 gas at 25°C and 1.00 atm pressure are needed to react completely with 70.25 grams of potassium hydride according to the chemical equation shown below? 2 KH (8) + O2 (g) → H20 (1) + K20 (8)

Answer 1

RI! (s) + O2 (9) - > H2O(l) + ķ015) Weight (HH) = 70.256 in c notes) = Weight (9) / ا (6 / له // و م = 70.259 40.10 g 1 mal h (males) - 1.75 a males of KH I males of KH reacted with = I make reacted with = 1 more of of a a 1.75 ales of Kh reacte with = I x1.75 moles of a = 0.87 nales af oz (0) - 0.87 P = I atm T = 25°C = 298 K R ( las constant) - 0.08205 L. atoo k most

a 1 x pu = nRT V = 0.87 x 0.08205 x 299 V = 21.272 Os must be required to carpletely read ka = 21.27L