Question

A normal population has a mean of 19 and a standard deviation of 5. a. Compute the z value associated with 22. (Round your answer to 2 decimal places.) Z 0.60| b. What proportion of the population is between 19 and 22? (Round z-score computation to 2 decimal places and your final answer to 4 decimal places.) Proportion c. What proportion of the population is less than 14? (Round z-score computation to 2 decimal places and your final answer to 4 decimal places.) Proportion

Answer 1

Solution! Given that, u=19 و دی P(x <22 이생 시그렇의 =P [ 2 2 3 =P | za 0.60l z value alo.co

by_ PC 19 CX 22) =P 19:19. <xus <22-147 =P 10.00 <2 <0.60] =p [z 40.60] -p [z<0.00] = 0.7257 - 0.5 = 0.2257 PL 19<x<22)=0-2257

PM 1 | 141 [14] = PT 2 4 - 1] = 158子 PxA4) = O•158F