What is the mass, in grams, of 9.41 • 10^24 Naturally occurring silicon consists of three...

Question

Question

What is the mass, in grams, of 9.41 • 10^24

science chemistry

Answer 1

Answer #1

Average atomic mass of silicon (Si) = 92.2297%(27.9769265327 amu) + 4.6832% (28.97649472 amu) + 3.0872% (29.97377022 amu) = 0

=========================================================================

Energy = 0.720 J Planks constant, h = 6.63x10-*Ls Velocity of light, c = 3x10 m/s 10 Wavelength of the the light, 1 = 615 mm

Answer 2

Similar Homework Help Questions

Silicon, which makes up about 25% of Earth's crust by mass, is used widely in the...

Silicon, which makes up about 25% of Earth's crust by mass, is used widely in the modern electronics industry. It has three naturally occurring isotopes, 28si, 29 Si, and 30Si. Calculate the atomic mass of silicon. Isotope 28Si 29Si 30Si Isotopic Mass (amu) 27.976927 28.976495 29.973770 Abudance % 92.22 4.69 3.09 0 27.9801 amu O 28.7260 amu O 28.9757 amu 28.0855 amu O 29.2252 amu
A hypothetical element (atomic mass = 17.144 amu) has three naturally occurring isotopes with isotopic masses...

A hypothetical element (atomic mass = 17.144 amu) has three naturally occurring isotopes with isotopic masses and natural abundances given below. Calculate the percent abundance of Isotope 1 Isotope Mass(amu) Abundance(%) 1 15.12326 ---- 2 16.13192 ---- 3 20.16658 29.60
The element carbon has two naturally occurring isotopes. The isotopic masses and abundances of these isotopes...

The element carbon has two naturally occurring isotopes. The isotopic masses and abundances of these isotopes are shown in the table below. Isotope 12c isotopic mass (amu) Abundance (%) 12.00 13.00 98.93 1.07 Calculate the average atomic mass of carbon to two digits after the decimal point. Number = _______ amu

The element chlorine has two naturally occurring isotopes. The isotopic masses and abundances of these isotopes...

The element chlorine has two naturally occurring isotopes. The isotopic masses and abundances of these isotopes are shown in the table. Isotope Isotopic mass (u) Abundance (%) Cl35Cl35 34.97 75.77 Cl37Cl37 36.97 24.23 Calculate the average atomic mass of chlorine to two digits after the decimal point. can someone explain how to do this and the solve it.
Natural silicon consists of three stable isotopes: 28Si, 29si and 30si. Which of these isotopes becomes...

Natural silicon consists of three stable isotopes: 28Si, 29si and 30si. Which of these isotopes becomes phosphorus when it is bombarded with neutrons? What isotope of phosphorus does it become?
Calculate based on the relative abundance of the three main isotopes of silicon the average atomic...

Calculate based on the relative abundance of the three main isotopes of silicon the average atomic mass of Siand compare your results with value in table elements (28Si(92.2%), 29Si(4.7%), (30Si(3.1%))

The element X has three naturally occurring isotopes. The masses (amu) and % abundances of the...

The element X has three naturally occurring isotopes. The masses (amu) and % abundances of the isotopes are given in the table below. The average atomic mass of the element is _ _amu. Isotope Abundance (%) Mass (amu) 221X 74.22 220.90 12.78 220.00 2187 13.00 218.10 2207 219.70 220.34 220.43 219.00 33.333
An element has three naturally occurring isotopes with masses as listed below. The average atomic mass...

An element has three naturally occurring isotopes with masses as listed below. The average atomic mass of this element is 28.08 amu. Determine the two missing percent abundances.^28X 27.98 amu % abundance =^29X 28.98 amu % abundance = 4.68 %^30X 29.97 amu % abundance =
In nature, the element X consists of two naturally occurring isotopes. 107X with abundance 54.84% and...

In nature, the element X consists of two naturally occurring isotopes. 107X with abundance 54.84% and isotopic mass 106.9051 amu and 109X with isotopic mass 108.9048 amu. Use the given information to calculate the atomic mass of the element X to an accuracy of .001% (Report your answer like this yyy.yyyy) Atomic Mass = amu.

The element Oxygen consists of three naturally occurring isotopes with masses 15.949915, 16.999131, and 17.999159 amu....

The element Oxygen consists of three naturally occurring isotopes with masses 15.949915, 16.999131, and 17.999159 amu. The relative abundances of these three isotopes are 99.76, 0.03800, and 0.2000 percent, respectively. From these data calculate the average atomic mass of Oxygen (in amu).