Question
Please refer to data set D
do the following: 4. For the acid in Option_ drogen(s) with an asterisk a) Draw a Lewis structure o (*). (Hint: Organic acids
1. For each data set, the volume of acid being analyzed is 10.00 mL and the concentration of NaOH is 0.100 M. Data Set Conc.
0 0
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Answer #1

4.

a)

The chemical formula of the acid is Н.РНО, .

P has 5 valence electrons.

Each O has 6 valence electrons , i.e. 3*6 = 18

Each H has one valence electron. i..e 1*3 = 3

Hence, total number of valence electrons in the molecule is 5+18+3 = 26

Now, we can draw the following Lewis structure with P as central atom.

:o : * H- P- 0- W -0 - I * acidic H

  

Note that P can have more than 8 electrons (expanded octet) around it as it has empty 3d orbital.

We can verify that our structure has 26 valence electrons by counting the bond pairs and lone pairs.

There are 7 bond pair and 6 lone pairs on O atoms. Hence, 13 bp+lp. Hence, total of 26 valence electrons.

The H atoms attached to O are acidic in nature as the electronegative O atom holds on to the bond electron pair making the deprotonation easier.

b)

The conjugate base of the above acid can be drawn by deprotonation of one of the acidic hydrogen.

H PHO3(acid) + H+ + HPH07 (con jugate base)

Hence, the Lewis structure of the conjguate base of the above acid in 4a) is

HP- :O : -I

c)

The structure in 4b) still has one more deprotonable H.

HPH07 (acid) + H+ + PHO-(conjugate base)

Hence, the conjugate base of the structure in 4b) can be drawn as

HP-

d)

Structure in 4b) acts as both an acid and as a base.

The equation in which it can act as a base is

H+ + HPH0, (base) = H,PHO3( conjugate acid)

The equation in which it can act as an acid is

HPH07 (acid) + H+ + PHO-(conjugate base)

This is possible because, structure in 4b) has one negative charge on O atom which can deprotonate an acid and thereby making the molecule a base. Also, it has a deprotonable H on it, hence, it can also act as an acid.

base part HP: ia : 0 :: acidic part

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