a) Apply One way Anova on Excel.
Group 1 = Yields at 300 Degree
Group 2 = Yields at 550 Degree
Group 3 = Yields at 500 Degree
Group 4 = Yields at 250 Degree
Group 5 = Yields at 375 Degree
Analysis of Variance Results
F-statistic value = 6.60854
P-value = 0.00356
Null Hypothesis:- Temperature does not affects yield.
Alternate Hypothesis:- Temperature affects yield
SInce P- value < 0.05, hence Null Hypothesis is true, which means Temperature does not affects yield

b)
The above chart shows Mean is highest for group 2, hence Yield is maximum at 550 degree
c)

.
X is the equation.
d) for x= 395 degrees
y = 17.06+0.024*(295) = 24.14mg
e)
Problem 2 An experiment was conducted to determine the affects of temperature on the mean yield...
Problem 2 In a process development study on yield, four factors were studied, each at two levels: time (A), concentration (B), pressure (C), and temperature (D). A single replicate of a 2 design was run and the resulting data are shown in the following table Yield (Ibs) 67 128 86 134 97 92 132 128 81 159 114 163 93 109 122 140 Actual Run Order 9 12 13 14 15 10 16 The factor level settings are as follows...
Problem 3 An experiment is conducted to determine whether the firing oven temperature affects the mean density of a certain type of brick. Multiple bricks are fired at different oven temperatures and the density is measured. The experiment led to the following data (shown in the order in which it was collected) e Minitab for this problem observation Oven Temperature (o Brick Densit 113.1 164.1 113.7 1900 2000 1800 1800 1950 1950 1900 1950 1900 2000 2000 1900 1950 1900...
1. Many companies use a incoming shipments of parts, raw materials, and so on. In the electronics industry, component parts are commonly shipped from suppliers in large lots. Inspection of a sample of n components can be viewed as the n trials of a binomial experimem. The outcome for each component tested (trialD will be that the component is classified as good or defective defective components in the lot do not exceed 1 %. Suppose a random sample of fiver...