A 120 g air-track glider is attached to a spring. The glider is pushed in 10.4 cm against the spring, then released. A student with a stopwatch finds that 10 oscillations take 12.0 s. What is the spring constant?
time period is given by
T = 12/10 = 1.2 second
angular frequency corresponding to the time period
w = 2 pi / T = 2 * 3.14/ 1.2 = 5.233 rad/s
sqrt ( k/m) = 5.233
sqrt ( k / 0.12) = 5.233
k = 3.286 N/m
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A 120 g air-track glider is attached to a spring. The glider is pushed in 10.4...
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