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1. A car traveling at a speed of vo = 52 m/s stops smoothly (that is,...

1. A car traveling at a speed of vo = 52 m/s stops smoothly (that is, its deceleration is constant) over a distance of d = 147 m. After the car has gone 1/3 of the stopping distance, what is its speed?

v1/3 =

2. An athlete sprinter 50m in 9.3 seconds, and then walks slowly back to the starting line in total time of 58 seconds. (Assume he runs in the positive direction.)  What is his average walking velocity?

vav =

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Answer #1

Use kinematics 0-vad 2d 522 2(147) -9.19 m/s2 Of stopping distance is 147 - 49 m The speed is 522+2(-9.19)(49) v= 65.96 m/s He took a time of t 58-9.3 48.7 s The walking speed is 50 48.7 m/s

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