Question

5) For the electrochemical cell Ni(s) i Ni?(1 M H (1M) H (1 atm) Ps), which one of the following changes will ALWAYS cause a decrease in the cell voltage? A) Decrease the ratio of P/[Ni?') B) Increase the ratio of PH,/[N?") C) Decrease the ratio of [NiY[H] D) Increase the ratio of [Ni?'VH1 E) Increase the ratio of [H*}*/PH, Answer: ) 4) Which of the following aqueous solutions has the highest boiling point (assume 100% dissociation for all soluble ionic compounds)? A) 0.10m Al(NO3)3 B) 0.11m Na2SO4C) 0.15m KCO D) 0.18m NaCl E) 0.35m C6H1206 Answer:

Answer 1

Q3)

Reduction Nils) tehtaas-> Nitton) + maig) v Oxidation Ni (s) friz" (IM) ||u+(IM) | 42 (leto) buce I l L idation otell reduction half cell - R The Ni²+] I nf [ht] ? Ecell = Ercell + RT [kt] ² - nf ĪNi²+ → when en [Ni2+] will increase [ut] Ecell decreases. option D is correct.

Q4) Elevation in boiling point

whenever a non-volatile solute is added to a pure solvent,  the elevation of boiling point (∆T_b) is observed which is directly proportional to the molal concentration of the solute in a solution.

∆T_b = K_​​​bm

AL(NO3)₂ → Al3+ + 3003 Oilm 0 0 0 Oulm Oilm X3 Total = 0.4m Massou Nat + 5042 oillm 0 0 2x0 ilm ollm Total = 0.33m

​​​​​​As K_​​​2​​​CO₃ has higher molality than others that's why it will elevate the boiling point maximum.

K₂CO 0.15m o 2K+ + cor o o 2x0.15 0.15m Total = 0.45m Nace Nat te- 0.18m 0 0 0 0,18m 0.18m . Total = 0.36m CH12O6 doesn't A dissociate 6.35m Total = 0.35m olm Al. (NO3)3 , Oum ollm Nag sou 0.33m 0.15 im Kg CO₂ I 0.45m 0.18 m Nall 10.36m 0.35 m CG H I 2O6. 20:35m

Option C is correct.