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A student ran the following reaction in the laboratory at 280 K: 2CH2Cl2(g) CH(g) + CC14(8) When she introduced 8.40x10-2 mol

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2CH₂U2 - 8.40x10-2 CHA(9) + CCl4 (9) I: C: 204 E: 8.40x10? zx x x=3.934102M Kc = [CHA] [cc] [CH₂Cl2]² = (x) (0) . (8.40x10? z

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