Here,
Slope of the calibration curve = 0.59 mM-1
Standard deviation of the blank measurements = 0.0059
We have,
Limit of detection = (3 x Standard deviation)/Slope
= (3 x 0.0059)/ 0.59 mM-1 = 0.03 mM
Limit of quantification = (10 x Standard deviation)/Slope
= (10 x 0.0059)/ 0.59 mM-1 = 0.1 mM
J 0 points) The detection limit for caffeine analysis must be calculated. Eight absorbance readings from...
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Low concentrations of thallium near the detection limit gave the following dimensionless instrument readings: 206.9,173.7.163.9,175.9, 220.9.161.7, 224.7, 203.3,136.3, and 207.1. Ten blanks had a mean reading of 42.1. The slope of the calibration curve is 1.76 times 10^9M^-1. Estimate the signal and concentration detection limits and the lower limit of quantitation for thallium. Signal Detection Limit: Concentration Detection Limit: Lower Limit of Quantitation:
Low concentrations of warfarin near the detection limit gave the dimensionless instrument readings: 203.3, 172.3, 160.3, 172.3, 217.3, 158.1, 221.1. 199.7, 132.7, and 203.5. Ten blanks had a mean reading of 56.3. The slope of the calibration curve is 3.55 x 10' M-!. Estimate the signal and concentration detection limits and the lower limit of quantitation for warfarin. signal detection limit: concentration detection limit: lower limit of quantitation:
summatize the following info and break them into differeng key points. write them in yojr own words
apartus
6.1 Introduction—The design of a successful hot box appa- ratus is influenced by many factors. Before beginning the design of an apparatus meeting this standard, the designer shall review the discussion on the limitations and accuracy, Section 13, discussions of the energy flows in a hot box, Annex A2, the metering box wall loss flow, Annex A3, and flanking loss, Annex...