Question

Problem 11. Consider the oscillator with the energy behavior displayed in Figure 2. Take the mass of the oscil- lating block to be 1 kg and the spring constant to be 100 N/m. Find the amplitude of the motion. 13 12 10 9 8 3 0.25 0.5 t (s) Us _KE-12.5J 0.75 Figure 2. Notice that the total energy is constant.

Answer 1

We know that

Total energy

E=kA^2/2

here E=12.5 J , k=100N/m ,A=? (Amplitude of the motion)

so

A^2=2E/k

=2×12.5/100

A^2=0.25

A=sqrt(0.25)

A=0.5 m. Answer