2. A steel plant operator wishes to change 100 kg of 25°C iron into molten iron...

Question

Question

science physics

Answer 1

Answer #1

Here , for iron

latent heat of iron = 272 kJ/Kg

specific heat of iron = 0.45 kJ/(Kg.degree C)

Now, mass of iron = 100 Kg

heat needed = heat for melting iron + heat for raising the temperature to 1538

heat needed = 100 * ((1538 - 25) * 0.45 + 272)

heat needed = 95285 kJ

the heat added is 95285 kJ

Answer 2

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