Question

6) A small conducting sphere is charged to-22μΟ. Then a second identical sphere (which initially has zero charge) is brought into contact with the charged sphere. After the charge equilibrates, the two spheres are separated by 0.52 m. What is the force between them?

Answer 1

As both spheres are identical , when the second sphere is brought into contact and charge equilibrates , the net charge (q) on each sphere will be

  

As both spheres are identical, when the second sphere is brought into contact and charge equilibrates, the net charge (q) on each sphere will be -22/2 mu C = -11 mu C = -11 times 10^-6 C The distance between the spheres is 0.52 m. So, net force between them will be F = 1/4 pi epsilon_0 r^2 or, F = 9 times 10^9 (-11 times 10^-6)^2/0.52^2 or, F = 4.03 N

The distance between the spheres is 0.52 m.

So, net force between them will be

or,

or,   

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