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12) Given the enthalpy changes: 0 Inn A+B → A+DE+F AH=-35 kJ•mol- AH = +20 kJ•mol All= +15 kJ.mol- F → C+E What is AH for th
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Answer #1

Reversing the last equation: E + C \rightarrow F The enthalpy is the negative of the enthalpy change of the forward reaction: \Delta H = -15 KJ/mol

Now adding the first two reactions and the equation we formed above: 2A + B + D \rightarrow 2F

This means we need to add the individual enthalpies of the three separate equations: -35 + 20 - 15 = -30 KJ/mol

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