Question

A sample of carbon dioxide gas occupies 10,903 mL at STP. What is the mass of the sample? QUESTION 2 A 598 mL sample of carbon dioxide gas, CO2, is collected at 1.72 atm and 36.7 °C. What is the mass of the carbon dioxide?

Answer 1

At STP I mole of any gas occupies 22-4142 let x' 10903 be hel = the mass 10.903L. of co, that occupies 22-414 L of gas area has - 10.903 L of gas has - Cross multiply 10.903 X 44 = X X 22-414 44g of coj. x' x= 10.9034 44 22.414 X= 21-40322

According to ideal gas law PV = nRT p is the pressure V is the volume n is number of moles R = 0.0821 L. atm. mol.kt t is the temperature in Kelvin. mass molar mass

-PU: HRT V=598 ml = 0.598 L. p=1.7gatr T= 36.7+273 = 309.7K. RT n= (1.72atm) (0.5981) (0.082 il-ath-mor"*") (309.7%) n: 0-०५० पर hole mass = nx molar mass mass = 0.040452 moles x 4 4 9 / mod = 1.72999.