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Describe in detail how you would make a series of four standards ranging from 1 to 100 ppm given the following constraints. a. Your stock solution is 1000 ppm. b. The available pipets have volumes of 2.00 mL, 3.00 mL, and 5.00 mL. c. The available volumetric flasks have volumes of 10.00 mL, 25.00 mL, 50.00 mL, and 100.00 mL. d. You need to make at least 10.00 mL of each of your four standards.

Answer 1

With given can do is solutions ; conditions , what we make the following I 1 ooo XV - Yox / 00 ppm ppm mL | V+ = 2mL IV+ = 4 mL I. 25mL of toppm solution So, UmL of 1000 ppm can be taken We have 1000 ppm Atock solution I in lots of 2mL each by Using Standard Molarity equation, 2 ml fripette in two turns My = NzV2 into a loome volumetric flask and Stock After dilution solution can be made. 1ooo XVt = 80 x 25 PPM II lome of 20ppm solution ppm ML We can make this by using 40ppm solution (forepared in step II) So, 2mL of lood ppm can be taken by MV = M₂ V2 a 2 mL ripette in 25mL of Volumetric Stock Desired flask and solution can be prepared. 40 xVt = 20 xlo ppm Ppm ML II. 5om of 60 ppm solution | V+ = 5 mL My = M₂ V2 : 5m2 of 40 ppm solution can be Stock Afterdilution taken by using a 5 ml pipette 1000 x V = 60 X 50 into a lomb volumetrur flask . Ppm mL - ppm Thus, the V+= 3 mL desired solution can I be prepared. so, 3 mL of loooppm can be taken in 50m2 volumetric flask and solution can be made. a I loomL of Hoppm Solution MV = May Aflerdilution stock