Question

Homework 5: Solutions (4 hours) Exercise 13.96 Part A me What is the molarity of ZnCl(aq) that forms when 16.0 g of zinc completely reacts with Cuci, (g) according to the following reaction (Assure a final volume of Zn(s) + CuCl(aq)--ZnCl, (aq) + Cu(s) 0 AED O mi? Submit Request Answer Provide Feedback

Answer 1

Following is the - complete Answer -&- Explanation: for the given: Question: in....typed format...

$\Rightarrow$Answer:

Final molarity: of  ZnCl₂ (aq) :   Final: [ ZnCl₂ ] =  1.255 M ( mol/L ) ( approx. )

$\Rightarrow$Explanation:

• Given:

1. Mass of zinc : = 16.0 g ( grams )
2. Final volume of the solution = 195.0 mL = 0.195 L ( Liters )
3. We know: molar mass of zinc = 65.39 g/mol  
4. balanced chemical equation: Zn (s) + CuCl₂ (aq) $\rightleftharpoons$ ZnCl₂ (aq) + Cu (s) ------- Equation - 1

• Step - 1:

​​​​​​​Using the above information: we get :

$\Rightarrow$ Number of moles of zinc =  ( mass of zinc ) / ( molar mass of zinc ) = ( 16.0 g ) / ( 65.39 g/mol ) = 0.2447 mol ( approx.)

$\Rightarrow$ From: Equation - 1: we get: the following molar ratio:

  Zn(s) : ZnCl₂ = 1 : 1

Therefore:

$\Rightarrow$ Moles of  ZnCl₂  : produced =  0.2447 mol ( moles )

• Step - 2:

​​​​​​​Therefore: we can see the following:

$\Rightarrow$   0.195 L ( Liters ), of the final solution, contains:  0.2447 mol ( moles ) of ZnCl₂ ....

$\Rightarrow$1.0 L ( Liters ) of the final solution , will contain: (0.2447 mol ) / ( 0.195 L ) =  1.255 mol/L   ( approx. )

• Answer:

​​​​​​​Therefore:

$\Rightarrow$ Molarity of ZnCl₂: in the final solution: will be: [ ZnCl₂ ] =   1.255 mol/L ( approx. )