Question

Part 2. (10pt) Determine AG for the ab H2O (liquid, -15 °C) → H2O (solid, -15 °C) CAG for the above spontaneous (irreversible) process (with 3.0 mol of water at 1 atm): 2. (40pt) 2.0-mole ideal gas with molar heat capacity Cyms undergoes the following two processes he following two processes, as shown in the P-V diagram on right. Process 1: A to B (A linear decreasing function) Process 2: B to C (constant pressure) Process 3: C to A (constant volume) Determine 4, W, AU, AH. AS for the first two processes in the following chart. Process 1 Process 2

Answer 1

Given noles of Molar heat Cap CCim 2 mole R 2 CpamSptR R 2

4al Process-1 Date: Page: Satm 49.6 2 Volume Lu) 24-81 Proce ss-1 (A B Wonkdene = area undo tue lna ABR ts due toenpanatoM 24 8x2 +1 24-82) wlbe area o ames 24 8 3 at d pant a tempereture at A PvnRT 2 4734-8 TP 62D K

tenp at peut e PV TB Page: Date 49-6 620k T2-T AT O Ase ening His an ideal a) DU= mcvdT ncvAT=O isot laus a tuas A cerin to ynamic =1514 J 7.5kJ Padcess-2 (B ) P= Const Poce-2 s isobasic DH mcp AT at Tep pont &620k

Cal" of ten at poit PV= nRT Page: Date: Te PV at poit c 2 X24.8 316 k 17 270 08 9AH-nCp AT 277Prt0Te 9TTRC0 620k 78-314X 310 J 18 041 kJ AU nCy AT 2XSRK-3)0 2 SKB-313 X310 J -12 886 kT -Pert dv P= Comtant Ve dw --P dy Work

w=P e- Vc) Date Page 24 8-496) atm +2 x24 8 atm 5.00KJ Calof AS fopocess- NAHT AS = AS R en 28.3 14x 2 2x8.314x0.693 11.2TK For process-2 P- Constat TaLTE 273R7 n 78.31470.693 40. 33 K

Pag 11.52J1K 75KT 5kJ Poocess roes-2 18.04 5D kJ - 40 33 -12.88 -18.04 KJ 24 PUeane ence Jain venby the caleuletion

In case of mismatch in answer, please once again verify the calculation.