Question
Please do 3.10
0 0 10 10 10 the head of a social services agency, you be of 20 social workers is ve lieve that your staff overworked compared with 10 loads for each worker are reported below for each the two years in question. Has the average caseload increased? Which measure of central tendency most appropriate to answer this question? Why? years ago. The case 2012 2002 42 75 82 50 52 50 57 49 52 50 52 59 60 65 68 60 65 50 58 64 69 60 50 45 65 60 65 60 60 60 ant 42 60 60
0 0
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Answer #1

using excel data analysis tool for descriptive statitics ,we get following output

2002 2012
Mean 54.25 Mean 60.3
Standard Error 1.666820168 Standard Error 2.085160602
Median 53.5 Median 60
Mode 50 Mode 60
Standard Deviation 7.454246405 Standard Deviation 9.325121701
Sample Variance 55.56578947 Sample Variance 86.95789474
Kurtosis -0.703314634 Kurtosis 0.592929296
Skewness 0.109119386 Skewness 0.348361902
Range 26 Range 40
Minimum 42 Minimum 42
Maximum 68 Maximum 82
Sum 1085 Sum 1206
Count 20 Count 20

for 2002

mean=54.25

median=53.5

mode=50

for 2012

mean=60.3

median=60

mode=60

since, for both years, mean median ,mode is nearly equal .so, data is symmetric

and for symmetric data , mean is used as measure of center of data

so, here, mean will be used as measure of center of data.

Here, we can observe that average caseload has increased from 2002 to 2012

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