Problem 2
This is the continuation of Problem 2 in Homework 3, but with questions about tradable permits.
Two steel factories are currently emitting 8,000 tons of pollution each (for a total of 16,000 tons). Pollution reduction (abatement) costs for Plant 1 are given by MCR1= 0.02Q and for Plant 2 by MCR2 = 0.03Q, where Q represents tons of abatement, and MCR the marginal cost of pollution reduction.
A). Without trading each firm have reduce 5000 tons of pollution,
So marginal cost of firm 1 of abatement=0.02Q
Total coat of firm 1 of abatement=0.01*Q^2
So cost of 5000 abatement=0.01*5000*5000=250,000
Same for firm 2
MCR=0.03Q
TCR=0.15*Q^2
TCR=0.015*5000*5000=375,000
B)MCR=1=0.02Q. ,MCR2=0.03Q
Q1=MCR/0.02. Q2= mcr/0.03
Q=q1+q1=mcr/0.02+mcr/0.03=5mcr/0.06
MCR=0.06Q/5
Abatement =10,000
MCR=0.06*10000/5=120
MCR1=0.02Q1. MCR2=0.03Q2
120=0.02Q1. 120=0.03Q2
Q1=6000. Q2=4000
So firm 2 will sell permit of 1000 tons .and firm 1 will buy it.
The permit price=abatement cost of those 1000 tons to firm 1
Permit price =0.01*6000*6000-0.01*5000*5000=110,000
Firm 1 net cost =0.01*6000*6000+110,000=347,000
Firm 2 net cost =0.015*4000*4000-110,000=130,000
Problem 2 This is the continuation of Problem 2 in Homework 3, but with questions about...
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the last fill in the blank
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Possible Solutions
Total Cost of eliminating 2 units of
pollution
The options for the first fill in the blank (Firm X) are: $295,
$120, $215, $320.
The options for the second fill in the blank (Firm Y) are:
$1250, $800, $1850, $1500
The options for the third fill in the blank (Firm Z) are: $180,
$250, $230, $100
The options for the forth fill in the blank are: $1490, $2420,
$1625, $1645
Firm X
Firm Y
Firm Z
Initial pollution...