Question

1. ANOVA is a statistical method for verifying the equality between some sample means b. a. some sample standard deviations c. some population standard deviations d some population means Salary information regarding male and female employees of a large company is shown below Sample Size Male (Pop. 1) Female (Pop. 2) 49 47 Sample Mean Salary (in $1,000) , Population Variance 2. The point estimate of the difference μ-μ, between the two population means is Y 7-44-3.0 3. The margin of error in the 95% confidence interval for the difference is 4. The 95% confidence interval for the difference μί-n is 5. If you are interested in testing whether or not the average salary of males is significantly greater than that of females, the value of the test statistic is 6. The p-value of the test iseL 7. At 5% significance level, the alternative hypothesis, μ? , is supported if the value of the test statistic z satisfies z2 At 5% significance level, the conclusion is that a the average salary of males is significantly greater than females b. the average salary of males is significantly lower than females c. the salaries of males and females are equal d. there is insufficient evidence to show that the average salary of males is significantly 8, greater than females A consumer advocate wants to compare the mean lengths of life of two brands of refrigerators, Brand A and Brand B. He collects data (in years) on the longevity of 40 refrigerators for brand A, and repeats the sampling for Brand B. Assuming the known populations variances and α-005, he obtained the following Excel output: z-Test: Two Sample for Means Mean Known Variance Observations Hypothesized Mean Difference Brand A Brand B 16.525 17.25 5.2 40 4.4 40 36 P(Zc z) one-tail z Critical one-tail P(Z<=z) two-tail z Critical two-tail -1.4799 0.0694 1.6449 0.1389 1.96

Answer 1

(3-4)

(5-8)