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the answer is 0.173... but how do I get it?
The local telephone company has a standby generator with a failure rate of 0.001 failures/hour to provide electrical power in
math   Statistics-And-Probability   
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Answer #1

P(failure of generator) =1-e-0.001*365*24 =0.999843

P(failure of electric system) =1-e-0.00023*365*24 =0.866653

electric power reliability of the year =1-P(both electric service and standby generator fails) =1-0.999843*0.866653

=0.133

option A is correct

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