Question

The P-value for a hypothesis test is shown. Use the P-value to decide whether to reject H when the level of significance is (a) a= 0.01, (b) a 0.05, and (c) a0.10. P 0.0749 (a) Do you reject or fail to reject Ho at the 0.01 level of significance? O A. Reject H because the P-value, 0.0749, is greater than a=0.01 O B. Fail to reject Ho because the P-value, 0.0749, is less than a = 0.01 O C. Reject Ho because the P-value, 0.0749, is less than a 0.01 O D. Fail to reject Ho because the P-value, 0.0749, is greater than a0.01 (b) Do you reject or fail to reject Ho at the 0.05 level of significance? O A. Fail to reject Ho because the P-value, 0.0749, is less than a 0.05 O B. Reject Ho because the P-value, 0.0749, is less than a 0.05. O C. Reject H because the P-value, 0.0749, is greater than a=0.05. O D. Fail to reject Ho because the P-value, 0.0749, is greater than 0.05 (c) Do you reject or fail to reject Ho at the 0.10 level of significance? O A. Reject Ho because the P-value, 0.0749, is less than a 0.10. O B. Fail to reject Ho because the P-value, 0.0749, is less than a 0.10 O C. Reject H because the P-value, 0.0749, is greater than a- 0.10 O D. Fail to reject H because the P-value, 0.0749, is greater than 0.10. Click to select your answer.

Answer 1

1) a) Option-D) Fail to reject H₀ . Because p-value , 0.0749 is greater than alpha = 0.01

b) Option-D) Fail to reject H₀ . Because p-value , 0.0749 is greater than alpha = 0.05

c) Option-A) Reject H₀ . Because p-value , 0.0749 is less than alpha = 0.1

2) p-value = P(Z < -2.05) = 0.0202

Option-A) 0.0202. Reject null hypothesis

3) test statistic = (890 - 870) / (127/sqrt(63)) = 1.25

critical value = Z_0.05 = 1.645

Rejection region, z > 1.645

Option-D) Fail to reject H₀ because the standardized test statistic is not in the rejection region