Question

ont Paragraph Styles Table 1: Temperature, Pressure and Volume Data Room (or regional) Pressure (atm) Temperature Final Volume of Initial Volume of O2 Collected Air of Distilled H20 Volume (after reaction) (mL) (Final Volume Initial Volume) of Air (mL) 24.3C 0.99 17ml 75ml 58ml Table 2: Reaction Time Data Time Reaction Total Reaction Time Reaction Ended Started Time 5:00:00 5:01:28:63 1:28.63 4. The pressure of oxygen gas inside the apparatuS can be calculated using the equation: PtotalPoz t Pwater vapor Look up the water vapor pressure (in atm) for the temperature you recorded in Part 1, Step 3 and calculate the pressure of the O2 gas (in atm). Show your work and include units. Temperature of room: 28.1 Pressure of water vapor: 0.0374 atm

Answer 1

Answer:

• Data:
  • Temperature room: 28.1 ºC
  • Vapor pressure of water vapor at 28.1 ºC: 0.0374 atm

To calculate the pressure of O_{2, it is necessary use the equation:}

_{Ptotal= Po + Pwater vapor}

_{Po=Protal Pwater vapor}

_where

• P_total = atmospheric pressure or room pressure = 0.99 atm
• P_{water vapor} = pressure of water vapor at temperature room = 0.0374 atm

then

Po 0.99 atm - 0.0374 atm = 0.952 atm

Conclusion: the pressure of O₂ is 0.952 atm