Question

A closed tube of internal diameter d = 50mm and external D = 60mm is subjected to an internal pressure of p = 10.1325Mpa, at the same time it is requested by the longitudinal force F = 40000N, a torque of Mt = 60000N.cm and a bending moment Mf = 50000N.cm (produces tensile stress in C). calculate in the point C located in the inner diameter of the tube, the tensions due to all the acting loads and the main tensions in that point.

EXAMEN PARCIAL DE MECANICA DE MATERIALES II 1. Un tubo cerrado de dimensiones d..r=50mm y d..60mm está sometido a una presión interior de p= 10.1325MP . Al mismo tiempo está solicitado por la fuerza longitudina F = 40000N, un momento torsor M-60000 N-cm y un momento flector Me 50000 N-cm (produce esfuerzo de tracción en a. Calcular en el punto designado C en el diámetro interior del tubo, las tensiones det a todas las cargas actuantes. (2.5 ptos.) b. Calcular las 3 tensiones principales y las 3 tensiones máximas de cizallamiento. (2.5 ptos.) C), calcular: un nunto de un sólido elástico, referida a un sistema 2019-6-

Answer 1

given, ntenal diameler d5omm outev diametev ntemal D-60mm premuve t0.1325MPo, F 40000N, M, 60000 N Cm 50000 N. Gm Mf = C Due tongthdunas borce F40000N norm al NiA sters Ccurs given by Lt0000N TH (602-502) A= σ=46-299 M Pa. Op do D, d- d Due to sheav stvers tovue M- 60000 N.Cm Due know Had at C',& it is iven OccuYs dd +2t CE distance bvom cente to point D-d = 2 2 60000N.XIO mmx25 =2 T (604-50) 32 60-50 J= Polav moment of inerHo 5m0 2 25mm 乙 = 22.77 MPa bending moment, Mc normal stres occuYs s given by Due to y2dista nce bvom N.A to Point 5×九 T 25 mm 50000x 10 X25N.mm 1aMoment of inevtia= T (d 644 1T604-50nm 64 - 37.951 MPa Sntevnal Pveare p lo 1325 MPa Now Axial Stves/1on s tverse due to Doupna stvemi a, Pd 10.132 5x 50 4X5 OXTT dxt - px 4 a 25.33 MPo Aoop /CYcumterental Pd SHEM 4も i0.1325 x50 Pd 2t 2 x5 50.66MPa P peay stvem 50.66-25-33 - Cat = 2 ( 2 2 x 21/ =Px dx て= 12.665MPa 2t