Question

Question 3c, how was the effective stress calculated for the depth of 2,6 and 10 m? How was the Cp calculated? Is sigma 1 the effective stress? What is sigma? Why d is 4?

1 3c In ε- Cp w-Σε disp ε. d do initial o Deformation depth d Strain (-) (m) 4 176.2 1.08 2 62 0.27 6 107 4 128.4 0.16 0.63 152 4 10 95.5 0.10 0.39 total 2.10 in 3) A 10 m wide and very long raft foundation with a load of 200 kPa is to be placed on a soil made up of a 2 m thick sand layer, followed by a 12 m thick clay layer and finally a deeper sand layer. The water table is at 2 m below the surface, with a capillary rise of 1 m. A separate monitoring well in the lower sand layer shows a phreatic surface at 6 m below the determined were: ysand upper dry = 18 kN/m°, ground surface. The material properties that were Ysand_upper_wet = 21 kN/m°, yelay = 18 kN/m2, ^sand_lower = 19 kN/m° and Cp, clay = 5 Draw the total stress, pore water pressure and effective stress profiles. [10 marks] a. b. Calculate the initial effective stresses and the effective stress changes at 2, 6 and 10 m below the top of the clay layer, underneath the centre-line of the foundation, after consolidation is complete. [10 marks] Calculate the deformation underneath the centre-line of the foundation, using 3 sub- C. layers for the clay, after consolidation is complete. [10 marks]

Answer 1

Soultion 3c

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