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A conducting rod has been attached to two helical springs and held stationary as shown in the figure. A uniform magnetic fiel

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Answer #1

The speed will vary as a sin function because of the simple harmonic motion. Now, the point Q will have positive charge for half cycle as the rod is going to the left [Lenz law = L(v x B)] and then when the rod is coming back, the charge will be negative, so the potential will be negative.

So, the option (4) is the answer for point Q.

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