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You toss a ball into the air at an initial angle of 40∘40∘ above the horizontal.
At what point in the ball’s trajectory does the ball have the smallest speed? (Neglect any effects due to air resistance).
at the highest point in its flight
just after it is tossed
just before it hits the ground
halfway between the ground and the highest point on the fall portion of the trajectory
halfway between the ground and the highest point on the rise portion of the trajectory
How will your answer to the previous question change if the initial angle is doubled, i.e., if the initial angle is 80∘80∘ ?
It depends on the initial value of the component of the velocity in the ?‑directiony‑direction .
The answer will be the same, because at the highest point of the flight, the speed is always the smallest regardless of the launch angle.
It depends on the initial value of the component of the velocity in the ?‑directionx‑direction .
Explain your reasoning:
optiion 1) atthe highest point of the flight because at the highest point vertical component of velocity is zero and hprizontal component is constant through out so at highest point projectile will have smallest speed
even if the angle is 80 degrees the answer will be same because at highest point of projectile launched at any angle vertical component is zero
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