Mean and St. Dev. Of a normal distribution are respectively 4700 and 500. Find the following probabilities . USE EXCEL. SHOW FORMULA
P(x<=5500)
P(x<=4500)
P(x<=4900)
P(x<=4300)
P(x>5500)
P(x>4500)
Mean and St. Dev. Of a normal distribution are respectively 4700 and 500. Find the following...
Given a normal distribution with mean equals 54 and st. dev. equals3, complete parts (a) through (d). Click here to view page 1 of the cumulative standardized normal distribution table.LOADING... Click here to view page 2 of the cumulative standardized normal distribution table.LOADING... a. What is the probability that Xgreater than49? P(Xgreater than49)equals nothing (Round to four decimal places as needed.) b. What is the probability that Xless than51? P(Xless than51)equals nothing (Round to four decimal places as needed.) c....
for a normal distribution with mean 50 and std dev of 5.2 find P90
A normal distribution has a mean of μ = 80 with σ = 12. Find the following probabilities. (a) p(X > 83) (b) p(X < 74) (c) p(X < 92) (d) p(71 < X < 89)
Assume that x has a normal distribution, with the specified mean and standard deviation. Find the indicated probabilities. P(x ≥ 6); μ = 17; σ = 5 0.486 0.243 0.986 0.493 0.014
If X has a normal distribution with mean 27.5, and standard deviation 9.2, find the "c" such that P(X>c) =0.55 Need step by step on how to solve using EXCEL
Using Excel - normal probabilities Consider the random variable x that follows a normal distribution, with a mean of μ = 54 and a standard deviation of σ = 4. You will select some of your answers to the questions that follow in this sample Excel spreadsheet: A B 1 P(x < 50.5) 2 P(49 < x < 51) In cell B1 of the sample spreadsheet, select the correct Excel formula for computing the probability that x is less than...
Consider a large population of interest. It's distribution is
normal and it's mean is 184 and standard deviation is 109. Let X =
a single observation.
(Round all probabilities to four decimals)
Consider a large population of interest. It's distribution is normal and it's mean is 184 and standard deviation is 109, Let X = a single observation (Round all probabilities to four decimals) a) Find P(X 189): le of 132 is taken. Let X = sample average of the...
Please show the work !
Find the value of Z for the standard normal distribution such that the area a) in the left tail is 0.1000 b) between 0 and Z is 0.2291 and Z is positive c) in the right tail is 0.0500 d) between 0 and Z is 0.3571 and Z is negative 1) 2) Find the following binomial probabilities using the normal approximation a) n- 70, p-0.30, P(x-18) b) n-200, p 0.70, P(133 x S 145) c)...
Let the random variable X follow a normal distribution with a mean of 17.1 and a standard deviation of 3.2. The normal probabilities are calculated using the table of standard normal distribution where the mean and standard deviations are, respectively: A) 1 and 1. B) 10 and 0. C) 0 and 1. D) 0 and 10.
If in a normal distribution, then using z-scores and drawing a labeled normal curve, find a) p(x>710) b) p(450 c) p(x<640) mean: 500 standard deviation: 100