Question

write a loop that processes a string and returns true if the string is a palindrome and false if it is not. A String is a palindrome if it is spelled the same forward as it is backward. For example, the words “joe”, “ age”, “pokemon”, “b”, “kayak” and “racecar” are all palindromes.

C++

I wrote a sample but not compiling...

#include"stdafx.h"

#include<iostream>

#include<string>

int main()

{

Int x = 0;

Int y= 0;

string word = “racecar”

x= 0;

y= word.length() -1;

while (x<y) {

if( word[x] != word [y]) (

cout<< “Not a Palindrome!” << endl;

return 0;

}

y++;

y--;

}

cout<< “ Yes a palindrome” << endl;

return 0;
}

Answer 1

#include <iostream>

#include <string.h>

using namespace std;

int isPalindrome(string s){

for(int i=0,j=s.length()-1;i<=j;i++,j--)

if(s[i]!=s[j])

return false;

return true;

}

// Driver program

int main(void)

{

if(isPalindrome("madam"))

cout<<"Is Palindrome";

else

cout<<"Is not a Palindrome";

}

IS #include <iostream> <string.h> 3 using namespace std 1 #include 4 5int isPalindrome (string s) for(int ію,j-s.length()-1;ioj ; i++ , j. . ) if(s[i-si]) return false; return true 10 11 Driver program 12 int main(void) 13 14 if(isPalíndrome("nadam")) 15cout<<"Is Palindrome"i 16 else 17 18 19 cout<<"Is not a Palindrome";