Question

Suspension point 1. Tuning a physical pendulum for highest frequency (problem 77 chapt. 13). [10] Please read the section "The pendulum" and "The physical pendulum" in chapter 13 before attempting this problem. A disk of radius R is suspended from a pivot somewhere between its centre and top edge (Fig. 13.34). Call the distance from the centre of mass to the centre of rotation.x. (a) Caclulate the moment of inertia of the disk when it is rotating about the suspension point. [2] (b) Find the formula for the angular frequency as a function of x. [4] (c) For what distance x will the period of the physical pendulum be a minimum? [4]

Answer 1

as the Suspension point Moment f inertial Suspension point Io=Iemt mx² about u Ti mat mx? = m A2+x2] Since, Io do? okt 2 - - mga sing For small D, .sinB No *. Io el tema -- mos o - (JO :-wo > warehouse wa 29 LR2+273] © Time period ,T= 21 - For period to be minimum. o must be maximum. - duo co = 20 - 293x43 (1972062) TREZ252; = 0 > 4x²= R +22² x=1 & * value o al for which time period will be minium.