Question

13) Find a period of oscillation of this physical pendulum. M1 = 0.5 kg , L1 = 1.00 m M2 = 1.0 kg, R2 = 20 cm, a solid disk 14). Describe the oscillation ( complete an expression x(t) for that oscillation). An object being displaced on the frictionless table to the left from equilibrium position at distance 0.3 m while it moving to the left with a speed 0.6 m/s. Coefficient of spring 100 N/m, and mass of the block 50 g. Draw a diagram and complete all calculations: A) Calculate the amplitude of the oscillation B) What is the initial Phase of this oscillation C) What is the angular frequency D) Write the equation x(t) E) Evaluate your answers using a unit circle. Evaluate your solutions by drawing a unit circle diagram.

Answer 1

9+ e a Compound structure Chich consists of a then god and a solid disk | M = 0.5 KS, 4 IM Let my s mass of sod 20.5 KS M Length of sod- Im OM SHORE, Ma mass of solid disk = 10 KG Ry = 20 cm, Re - Radius of a solid disk Solid disk 20 cm 50.2 m Moment of gnertia of total structure is the Endividual Sum of the moment of inertia of rod and solid disk. Here the rod of length Li rotatinê mh rotating aboret and aboret its end solid dick of radius Rerrotating abo its end nie about Point P. cohose center Se Dotating about an axes Shifted by distance 'htRg. Moment of inertia of sod=&mrt - 0.5 kg) x (Im 3 moment of inestia of rod = 0,16666F kom moment of inestea of solid disk abort et Center & = X 1.03 * 0.2m) = 0,02 kg.m2- Beet herce moment of Enertia can be calculated using Parcalled axis theorem Parcallel-axis : I center of mag tima. Sparalel-axis – m a male, tre & 1.068. (0.2) + 1.0 kg *( 1m +0.2 m) = (0.02 + 1.2) es m? - 1.22 Kg. m2 Trotal= 2 4 +3mdr tmull+RF = 5m Lit Esmak tima Cer} à Deotal= (0.1666 + 1.22) G. m? = 1.386 KBrm?

dem - Emixi 0.5 x(23) 41.08 1.2 107 lads 0.5x0.6 + 1.2. Emi 1.5 0.5410 dems 0.3412 103 is a 4.5 1.6 = 1.0cm. 20cm. T and more = 291 2x10 - att hitta 1.386 1.386 15 x 9.8 x 1.0 14.7 >> T = R1 0.094285 = 21% 0.30705978 = 1.929 see T = 1.929 see Anes