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5. Show the cross of a red eyed female (heterozygous) and a red eyed male What are the genotypes of the parents? How many of

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Answer #1

5. Xw+Xw X Y

Red-eyed female x red eyed male

Xw+ Xw
XW

Xw+XW

Red eyed female

XwXw

white eyed female

Y

Xw+Y

red eyed male

XwY

white eyed male

white eyed male -25%

white eyed female-25%

red eyed female- 25%

red eyed male- 25%

6. male haemophiliac x female carrier

XhY x XHXh

Xh Y
XH

XHXh

carrier daughter

XHY

normal son

Xh

XhXh

haemophiliac daughter

XhY

haemophiliac son

50% probability of being haemophilic in their children.

7. XHXh x XHY

carrier female x normal male

XH Xh
XH

XHXH

Normal female

XHXh

carrier female

Y

XHY

normal male

XhY

haemophiliac male

25% of haemophilia in the children and that too in males.

8. Xh Xh x XHY

Female haemophiliac x normal male

Xh Xh
XH

XHXh

carrier female

XHXh

carrier female

Y

XhY

haemophiliac female

XhY

haemophiliac female

50% of their children will be haemophiliac and these children will be sons or males.

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