expansion due to temperature change = alpha*change in temp* original length
alpha = coefficient of thermal expansion = 7.2*10-6 per degree F
expansion due to temperature change = 7.2*10-6 *(120-30)*40 = 0.02592 feet
so expansion allowed =0.02592 feet
QUESTION 4 What should be the separation between successive 40 feet steel rails (laid end to...
The 40-ft long A-36 steel rails on a train track are laid with a small gap between them to allow for thermal expansion. Determine the total required gap, 2*6, so that the rails just touch one another when the temperature is increased from T1 -20°F to T2 90 °F. If the rails were installed at -20 °F with this gap, what would be the axial force in the rails if the temperature were to rise to T3 = 110 °F....
Steel train rails are laid in 14.0-m-long segments placed end to end. The rails are laid on a winter day when their temperature is -5.0 ∘C. How much space must be left between adjacent rails if they are just to touch on a summer day when their temperature is 33.0 ∘C? If the rails are originally laid in contact, what is the stress in them on a summer day when their temperature is 33.0 ∘C? Please answer both questions
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Space? vetween the **9. Steel rails 20 m lo between the rails to allow laid on a cold winter day at -10° C. How much space must be left to allow for expansion at a summer temperature of 40°C the aluminum cap is too hard to unscrew on a new illeri *+10. If the aluminum a
3. Steel railroad rails 18,2880 m long are laid on a winter day when the temperature is -6,00 °C. How much space must be left between rails if they are just to touch on a summer day when the temperature is 43 °C? (4)
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