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Use the principle of superposition to determine the component of the current i through R3 that is due to Vs2. (Round the fina
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RM asi ② ZR1 2 2 3 {RI Į ( 3 23 RS to we need find i through R3 due to use deactivate we have the usi ie reduce voltage to o.Rx = 7.5 X 1.5 1.25 7.5+ 1.5 2 T X . -1.25n la { R3= 10.52 ? Vg2 ( Rgi Applying kuL to inner loop. - V2 + Rzi, ut Rsico. - whsolving 6 and ② 811+2 12 = 450 x 2 21; + 13.7512= 450 x 8 16 1,tui2=900 1611 + 110 12 = 3600. o 6 G o -10612=-2700 iz - 2700

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