Question

Part A able How many moles of NH3 can be produced from 18.0 mol of H2 and excess N2? Express your answer numerically in moles. Vlew Available Hint(s) he ucts V ΑΣφ ? e. mol NH3 Submit Part B can be produced from 3.78 mol of Ng and excess H2. How many grams of NH3 Express your answer numerically in grams. View Available Hint(s)

Answer 1

Part A

Answer

12mol

Explanation

N2(g) + 3H2(g) -------> 2NH3(g)

stoichiometrically , 3moles o H2 produces 2moles of NH3

So,

Number of moles of NH3 produced by 18moles of H2 = (2/3)×18mol = 12mol

Part B

Answer

128.82g

Explanation

N2(g) + 3H2(g) ------> 2NH3(g)

stoichiometrically, 1mole of N2 produce 2moles of NH3

Number of moles of NH3 produced by 3.78moles of N2 = 3.78mol × 2 = 7.56mol

mass = number of moles × molar mass

mass of NH3 can be produced = 7.56mol × 17.04g/mol= 128.82g