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3H2(g)+N2(g)→2NH3(g) Part A: How many moles of NH3 can be produced from 12.0 mol of H2...

3H2(g)+N2(g)→2NH3(g)

Part A: How many moles of NH3 can be produced from 12.0 mol of H2 and excess N2? = 8.00 mol

I need answers for Part B-D

Part B: How many grams of NH3 can be produced from 3.75 mol of N2 and excess H2?

Part C: How many grams of H2 are needed to produce 11.79 g of NH3?

Part D: How many molecules (not moles) of NH3 are produced from 5.00×10−4 g of H2?

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Answer #1

here the stoichiometry plays an important role

we have to convert weight of substance to mole and vice versa according to stoichiometriy

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