Question

3H2 + N2 -> 2NH3

How many grams of H, are needed to produce 10.31 g of NH?! Express your answer numerically In grams. View Available Hint(s) IVO AQ RO 0 ? 8H Submit Previous Answers X Incorrect; Try Again; 2 attempts remaining Part D How many molecules (not moles) of NH3 are produced from 3.33x10-4 g of H? Express your answer numerically as the number of molecules. View Available Hint(s) * 0 | ΑΣφ

Answer 1

| 1 mol NH3 =0 6054 mol NHÀ Equation: N, + 3H2 → 2NH No of moles of NH, = 10.31 g x-mol 17.03 g 3 mol H, 2.016 g Amount of H, needed = 0.6054 mol NH, 2 mol NHÀ 1 mol H2 = 1.831 g - - - - - - - - --- - Equation: N, + 3H2 + 2NH, No of moles of H,= 3.33x10* g * 1 mol H2 =1652x10* mol H, 8 * 2.016 g roduced=1.652x10* mol H2X 3 mol H, Amount of NH, produced = 1.652x10+ mol H 2 mol NH; 6.023x102 molecules 1 mol NH, = 6.63x10 molecules