Consider the following balanced reaction between hydrogen and nitrogen to form ammonia: 3H2(g) + N2(g)→2NH3(g) How...

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Consider the following balanced reaction between hydrogen and nitrogen to form ammonia: 3H2(g) + N2(g)→2NH3(g) How...

Consider the following balanced reaction between hydrogen and nitrogen to form ammonia: 3H2(g) + N2(g)→2NH3(g) How many moles of NH3 can be produced from 18.0 mol of H2 and excess N2? Express the number of moles to three significant figures

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Answer 1

Answer #1

H₂ is the limiting reagent here as N₂ is used in excess.

Moles of H₂ = 18.0 mol

From the balanced equation given in the problem, it is clear that 3 mol of H₂ give 2 mol of NH₃

Therefore, 18.0 mol of H₂ give = (2 mol x 18.0 mol)/3 mol = 12.0 mol of NH₃

Hence, the moles of NH₃ that can be produced = 12.0 mol

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Answer 2

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