Consider the following balanced reaction between hydrogen and nitrogen to form ammonia: 3H2(g) + N2(g)→2NH3(g) How...
Consider the following balanced reaction between hydrogen and nitrogen to form ammonia: 3H2(g) + N2(g)→2NH3(g) How many moles of NH3 can be produced from 18.0 mol of H2 and excess N2? Express the number of moles to three significant figures
Homework Answers
H2 is the limiting reagent here as N2 is used in excess.
Moles of H2 = 18.0 mol
From the balanced equation given in the problem, it is clear that 3 mol of H2 give 2 mol of NH3
Therefore, 18.0 mol of H2 give = (2 mol x 18.0 mol)/3 mol = 12.0 mol of NH3
Hence, the moles of NH3 that can be produced = 12.0 mol
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