Question

Nitrogen and hydrogen react to form ammonia according to the following balanced equation: N₂(g)+3H₂(g)=2NH₃(g). Calculate the number of moles of hydrogen required to react with 0.0723 mole of nitrogen, and the number of moles of ammonia that will form.

Answer 1

N₂(g)+3H₂(g)=2NH₃(g)

From the above equation, it is clear that 1 mole of nitrogen will react with 3 moles of hydrogen to give 2 moles of ammonia.

Now,

for 1 mole of nitrogen, 3 moles of hydrogen is required

Therefore, 0.0723 moles of nitrogen, required quantity of hydrogen = 3 x 0.0723 = 0.217 moles

Thus, the number of moles of hydrogen required to react with 0.0723 mole of nitrogen = 0.217 moles

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1 mole of nitrogen will produce 2 moles of ammonia

Therefore, 0.0723 moles of nitrogen will produce = 2 x 0.0723 = 0.145 moles

Hence, the number of moles of ammonia will form = 0.145 moles